mysqli_report

(PHP 5)

Description

mysqli_report() is a powerful function to improve your queries and code during development and testing phase. Depending on the flags it reports errors from mysqli function calls or queries which don't use an index (or use a bad index).

Возвращаемые значения

Возвращает TRUE в случае успешного завершения или FALSE в случае возникновения ошибки.

Смотрите также

mysqli_debug() и mysqli_dump_debug_info().

Примеры

Пример 1. Object oriented style <?php /* activate reporting */ mysqli_report(MYSQLI_REPORT_ALL); $mysqli = new mysqli("localhost", "my_user", "my_password", "world"); /* check connection */ if (mysqli_connect_errno()) {     printf("Connect failed: %s\n", mysqli_connect_error());     exit(); } /* this query should report an error */ $result = $mysqli->query("SELECT Name FROM Nonexistingtable WHERE population > 50000"); /* this query should report a warning */ $result = $mysqli->query("SELECT Name FROM City WHERE population > 50000"); $result->close(); $mysqli->close(); ?>